0=-4.9t^2+2.95t+1.2

Solution for 0=-4.9t^2+2.95t+1.2 equation:

0=-4.9t^2+2.95t+1.2

We move all terms to the left:

0-(-4.9t^2+2.95t+1.2)=0

We add all the numbers together, and all the variables

-(-4.9t^2+2.95t+1.2)=0

We get rid of parentheses

4.9t^2-2.95t-1.2=0

a = 4.9; b = -2.95; c = -1.2;
Δ = b2-4ac
Δ = -2.952-4·4.9·(-1.2)
Δ = 32.2225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.95)-\sqrt{32.2225}}{2*4.9}=\frac{2.95-\sqrt{32.2225}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.95)+\sqrt{32.2225}}{2*4.9}=\frac{2.95+\sqrt{32.2225}}{9.8}
$